Arc Length and Sector Area

Calculate arc lengths and sector areas using radian measure.

Arc Length and Sector Area

Prerequisites

Before studying this topic, make sure you understand:

  • Converting between degrees and radians
  • Basic circle geometry (radius, circumference, area)

Arc Length

Arc length is the distance along the curved edge of a circle between two points.

The Formula (Radians)

For a circle with radius rr and central angle θ\theta (in radians):

s=rθs = r\theta

Where:

  • ss = arc length
  • rr = radius
  • θ\theta = central angle in radians

Why This Formula Works

The circumference of a full circle is 2πr2\pi r. A full rotation is 2π2\pi radians.

So the arc length for angle θ\theta is: s=θ2π×2πr=rθs = \frac{\theta}{2\pi} \times 2\pi r = r\theta

Examples

Example 1: A circle has radius 5 cm. Find the arc length for a central angle of π3\frac{\pi}{3} radians.

s=rθ=5×π3=5π3 cm5.24 cms = r\theta = 5 \times \frac{\pi}{3} = \frac{5\pi}{3} \text{ cm} \approx 5.24 \text{ cm}

Example 2: A circle has radius 10 inches. Find the arc length for a central angle of 60°60°.

First, convert to radians: 60°=π360° = \frac{\pi}{3} radians

s=10×π3=10π3 inches10.47 inchess = 10 \times \frac{\pi}{3} = \frac{10\pi}{3} \text{ inches} \approx 10.47 \text{ inches}

Example 3: If an arc has length 12 cm and the radius is 8 cm, find the central angle in radians.

θ=sr=128=32 radians=1.5 radians\theta = \frac{s}{r} = \frac{12}{8} = \frac{3}{2} \text{ radians} = 1.5 \text{ radians}

Sector Area

A sector is a "slice" of a circle, like a piece of pie.

The Formula (Radians)

For a circle with radius rr and central angle θ\theta (in radians):

A=12r2θA = \frac{1}{2}r^2\theta

Where:

  • AA = sector area
  • rr = radius
  • θ\theta = central angle in radians

Why This Formula Works

The area of a full circle is πr2\pi r^2. A full rotation is 2π2\pi radians.

So the sector area for angle θ\theta is: A=θ2π×πr2=12r2θA = \frac{\theta}{2\pi} \times \pi r^2 = \frac{1}{2}r^2\theta

Examples

Example 1: Find the area of a sector with radius 6 cm and central angle π4\frac{\pi}{4} radians.

A=12r2θ=12(6)2×π4=12(36)×π4=36π8=9π2 cm2A = \frac{1}{2}r^2\theta = \frac{1}{2}(6)^2 \times \frac{\pi}{4} = \frac{1}{2}(36) \times \frac{\pi}{4} = \frac{36\pi}{8} = \frac{9\pi}{2} \text{ cm}^2

Example 2: A pizza with radius 12 inches is cut into 8 equal slices. What is the area of one slice?

Each slice has central angle: 2π8=π4\frac{2\pi}{8} = \frac{\pi}{4} radians

A=12(12)2×π4=12(144)×π4=144π8=18π in256.55 in2A = \frac{1}{2}(12)^2 \times \frac{\pi}{4} = \frac{1}{2}(144) \times \frac{\pi}{4} = \frac{144\pi}{8} = 18\pi \text{ in}^2 \approx 56.55 \text{ in}^2

Example 3: A sector has area 20π20\pi cm² and radius 10 cm. Find the central angle.

θ=2Ar2=2(20π)(10)2=40π100=2π5 radians\theta = \frac{2A}{r^2} = \frac{2(20\pi)}{(10)^2} = \frac{40\pi}{100} = \frac{2\pi}{5} \text{ radians}

Combined Problems

Example: A circle has radius 15 m. A sector has central angle 2π3\frac{2\pi}{3} radians. Find both the arc length and sector area.

Arc length: s=rθ=15×2π3=10πs = r\theta = 15 \times \frac{2\pi}{3} = 10\pi m 31.42\approx 31.42 m

Sector area: A=12r2θ=12(15)2×2π3=12(225)×2π3=450π6=75πA = \frac{1}{2}r^2\theta = \frac{1}{2}(15)^2 \times \frac{2\pi}{3} = \frac{1}{2}(225) \times \frac{2\pi}{3} = \frac{450\pi}{6} = 75\pi235.62\approx 235.62

Important Notes

⚠️ These formulas only work when the angle is in radians!

If you're given degrees, convert to radians first.

Real-World Applications

  • Architecture: Circular windows, arches, domes
  • Engineering: Gears, pulleys, rotating machinery
  • Sports: Basketball court three-point lines, running tracks
  • Landscaping: Curved garden beds, irrigation coverage
  • Navigation: Distance along Earth's surface (great circle routes)

📚 Practice Problems

No example problems available yet.