Arithmetic Sequences

Patterns and formulas for arithmetic sequences

Arithmetic Sequences

What is a Sequence?

A sequence is an ordered list of numbers called terms.

Example: 2, 4, 6, 8, 10, ...

Notation:

  • a₁ = first term
  • a₂ = second term
  • a₃ = third term
  • aₙ = nth term

Types of sequences:

  • Arithmetic (constant difference)
  • Geometric (constant ratio)
  • Other patterns

What is an Arithmetic Sequence?

An arithmetic sequence has a constant difference between consecutive terms.

Examples:

  • 3, 7, 11, 15, 19, ... (add 4 each time)
  • 20, 15, 10, 5, 0, ... (subtract 5 each time)
  • 1, 1.5, 2, 2.5, 3, ... (add 0.5 each time)

The constant difference is called the common difference (d).

Finding the Common Difference

The common difference (d) is found by subtracting consecutive terms.

Formula: d = a₂ - a₁ = a₃ - a₂ = aₙ₊₁ - aₙ

Example 1: 5, 9, 13, 17, 21

d = 9 - 5 = 4 Check: 13 - 9 = 4 ✓ Common difference: d = 4

Example 2: 30, 25, 20, 15, 10

d = 25 - 30 = -5 Common difference: d = -5 (decreasing sequence)

Example 3: 2, 5, 8, 11, 14

d = 5 - 2 = 3 Common difference: d = 3

Example 4: 7, 7, 7, 7, 7

d = 7 - 7 = 0 Common difference: d = 0 (constant sequence)

Writing the Next Terms

Add the common difference to find the next term.

Example 1: Find next 3 terms of 4, 7, 10, 13, ...

d = 3 Next terms: 13 + 3 = 16 16 + 3 = 19 19 + 3 = 22

Sequence: 4, 7, 10, 13, 16, 19, 22, ...

Example 2: Find next 3 terms of 100, 95, 90, 85, ...

d = -5 Next terms: 85 - 5 = 80 80 - 5 = 75 75 - 5 = 70

Sequence: 100, 95, 90, 85, 80, 75, 70, ...

The Explicit Formula

The explicit formula (or nth term formula) lets you find any term directly.

Formula: aₙ = a₁ + (n - 1)d

where:

  • aₙ = nth term
  • a₁ = first term
  • n = position number
  • d = common difference

Example 1: Find the 20th term of 3, 7, 11, 15, ...

a₁ = 3, d = 4, n = 20

a₂₀ = 3 + (20 - 1)(4) a₂₀ = 3 + 19(4) a₂₀ = 3 + 76 a₂₀ = 79

Example 2: Find the 50th term of 100, 95, 90, ...

a₁ = 100, d = -5, n = 50

a₅₀ = 100 + (50 - 1)(-5) a₅₀ = 100 + 49(-5) a₅₀ = 100 - 245 a₅₀ = -145

Example 3: Find the 15th term of 2, 9, 16, 23, ...

a₁ = 2, d = 7

a₁₅ = 2 + (15 - 1)(7) a₁₅ = 2 + 98 a₁₅ = 100

Writing the Explicit Formula

Given the sequence, write the formula for aₙ.

Example 1: 5, 8, 11, 14, 17, ...

a₁ = 5, d = 3

Formula: aₙ = 5 + (n - 1)(3) Simplified: aₙ = 5 + 3n - 3 = 3n + 2

Example 2: 20, 17, 14, 11, 8, ...

a₁ = 20, d = -3

Formula: aₙ = 20 + (n - 1)(-3) Simplified: aₙ = 20 - 3n + 3 = -3n + 23

Example 3: 4, 9, 14, 19, 24, ...

a₁ = 4, d = 5

Formula: aₙ = 4 + (n - 1)(5) = 5n - 1

Finding Which Term Has a Given Value

Set aₙ equal to the value and solve for n.

Example 1: In the sequence 3, 7, 11, 15, ..., which term equals 99?

Formula: aₙ = 3 + (n - 1)(4) = 4n - 1

Set equal: 4n - 1 = 99 4n = 100 n = 25

The 25th term equals 99.

Example 2: In sequence 50, 46, 42, 38, ..., which term equals 2?

Formula: aₙ = 50 + (n - 1)(-4) = -4n + 54

-4n + 54 = 2 -4n = -52 n = 13

The 13th term equals 2.

Example 3: In sequence 1, 6, 11, 16, ..., which term equals 101?

aₙ = 1 + (n - 1)(5) = 5n - 4

5n - 4 = 101 5n = 105 n = 21

The 21st term is 101.

Recursive Formula

A recursive formula defines each term using the previous term.

General form: aₙ = aₙ₋₁ + d with a₁ given

Example 1: 5, 9, 13, 17, ...

a₁ = 5 aₙ = aₙ₋₁ + 4

Example 2: 30, 25, 20, 15, ...

a₁ = 30 aₙ = aₙ₋₁ - 5

Recursive vs. Explicit:

  • Recursive: need previous term
  • Explicit: can find any term directly

Graphing Arithmetic Sequences

Plot points (n, aₙ) where n is term number.

Example: 2, 5, 8, 11, 14, ...

Points: (1, 2), (2, 5), (3, 8), (4, 11), (5, 14)

Observation: Points lie on a straight line! Slope of line = common difference d

The graph is discrete (individual points), not continuous.

Arithmetic Means

An arithmetic mean between two numbers is the average.

Example: Find arithmetic mean between 10 and 20.

Mean = (10 + 20)/2 = 15

Multiple means: Insert numbers to form arithmetic sequence.

Example: Insert 3 arithmetic means between 5 and 25.

We need: 5, ?, ?, ?, 25 (5 terms total)

a₁ = 5, a₅ = 25, n = 5

Use formula: 25 = 5 + (5 - 1)d 25 = 5 + 4d 20 = 4d d = 5

Sequence: 5, 10, 15, 20, 25

Sum of Arithmetic Sequence

The sum of n terms (Sₙ) has a special formula.

Formula 1: Sₙ = n(a₁ + aₙ)/2

Formula 2: Sₙ = n[2a₁ + (n - 1)d]/2

Example 1: Find sum of first 10 terms of 3, 7, 11, 15, ...

First find a₁₀: a₁₀ = 3 + (10 - 1)(4) = 39

Use Formula 1: S₁₀ = 10(3 + 39)/2 S₁₀ = 10(42)/2 S₁₀ = 210

Example 2: Find sum: 2 + 5 + 8 + ... (20 terms)

a₁ = 2, d = 3, n = 20

Use Formula 2: S₂₀ = 20[2(2) + (20 - 1)(3)]/2 S₂₀ = 20[4 + 57]/2 S₂₀ = 20(61)/2 S₂₀ = 610

Example 3: Sum of 1 + 2 + 3 + ... + 100

a₁ = 1, aₙ = 100, n = 100

S₁₀₀ = 100(1 + 100)/2 S₁₀₀ = 100(101)/2 S₁₀₀ = 5,050

Why the Sum Formula Works

Visual explanation: Sum = 1 + 2 + 3 + 4 + 5 Reverse = 5 + 4 + 3 + 2 + 1 Add: 6 + 6 + 6 + 6 + 6 = 5 × 6 = 30 So sum = 30/2 = 15

General: Sₙ = n(first + last)/2

Applications: Saving Money

Example: Save 10firstweek,10 first week, 15 second week, $20 third week, etc. How much saved after 20 weeks?

a₁ = 10, d = 5, n = 20

First find a₂₀: a₂₀ = 10 + (20 - 1)(5) = 105

Sum: S₂₀ = 20(10 + 105)/2 S₂₀ = 20(115)/2 S₂₀ = $1,150

Applications: Seating

Example: Theater has 20 rows. First row has 15 seats, each row has 2 more seats than previous. How many total seats?

a₁ = 15, d = 2, n = 20

a₂₀ = 15 + 19(2) = 53 seats in last row

Total: S₂₀ = 20(15 + 53)/2 = 20(68)/2 = 680 seats

Applications: Falling Objects

Example: Object falls 16 ft in 1st second, 48 ft in 2nd second, 80 ft in 3rd second, etc. How far in 10 seconds?

Sequence: 16, 48, 80, ... d = 32

a₁₀ = 16 + 9(32) = 304 ft in 10th second

Total distance: S₁₀ = 10(16 + 304)/2 = 1,600 ft

Identifying Arithmetic Sequences

Check if sequence is arithmetic: Calculate differences between consecutive terms. If all equal, it's arithmetic!

Example 1: 3, 6, 12, 24, ... 6 - 3 = 3 12 - 6 = 6 (different!) NOT arithmetic (this is geometric)

Example 2: 5, 8, 11, 14, ... 8 - 5 = 3 11 - 8 = 3 14 - 11 = 3 ✓ Arithmetic with d = 3

Common Mistakes to Avoid

  1. Confusing term number with term value a₅ = 20 means 5th term is 20, not "a times 5"

  2. Wrong formula Use aₙ = a₁ + (n - 1)d, not aₙ = a₁ + nd

  3. Arithmetic errors with negatives If d = -3, then add -3 (subtract 3)

  4. Forgetting to find d first Always identify common difference!

  5. Not checking if sequence is arithmetic Calculate differences to verify

  6. Mixing up sum formulas Sₙ needs (a₁ + aₙ)/2, not (a₁ + d)

Arithmetic vs. Geometric

Arithmetic: constant difference (add/subtract)

  • 2, 5, 8, 11, ... (add 3)

Geometric: constant ratio (multiply/divide)

  • 2, 6, 18, 54, ... (multiply by 3)

Other patterns:

  • 1, 4, 9, 16, ... (perfect squares)
  • 1, 1, 2, 3, 5, 8, ... (Fibonacci)

Real-World Examples

Arithmetic sequences appear in:

  • Stacking objects (height increases by constant)
  • Straight-line depreciation (value decreases by constant)
  • Regular savings plans
  • Seating arrangements
  • Odometer readings at constant speed
  • Rental fees (base + per day)

Quick Reference

Common difference: d = a₂ - a₁

Explicit formula: aₙ = a₁ + (n - 1)d

Recursive formula: aₙ = aₙ₋₁ + d

Sum formula: Sₙ = n(a₁ + aₙ)/2

Practice Strategy

Level 1: Find common difference

  • Given sequence, find d

Level 2: Find next terms

  • Continue the pattern

Level 3: Find specific term

  • Use explicit formula

Level 4: Write formula

  • Given sequence, find aₙ

Level 5: Applications

  • Word problems with sequences

Tips for Success

  • Always find d first
  • Memorize: aₙ = a₁ + (n - 1)d
  • Check work by calculating a few terms
  • Verify sequence is arithmetic before using formulas
  • Draw diagrams for word problems
  • Remember n is position number, not the term value
  • Practice identifying patterns
  • Use sum formula for long sequences
  • Graph sequences to visualize
  • Connect to linear functions (same slope as d)

📚 Practice Problems

1Problem 1easy

Question:

Find the next three terms: 5, 8, 11, 14, ...

💡 Show Solution

Step 1: Find the common difference (d): d = 8 - 5 = 3 Check: 11 - 8 = 3, 14 - 11 = 3 ✓

Step 2: Add the common difference to find the next terms: 5th term: 14 + 3 = 17 6th term: 17 + 3 = 20 7th term: 20 + 3 = 23

Step 3: Verify the pattern: 5, 8, 11, 14, 17, 20, 23 (each term increases by 3)

Answer: 17, 20, 23

2Problem 2easy

Question:

Find the common difference: 5,9,13,17,...5, 9, 13, 17, ...

💡 Show Solution

Subtract consecutive terms:

d=95=4d = 9 - 5 = 4

Check: 139=413 - 9 = 4

Answer: Common difference = 44

3Problem 3easy

Question:

Is the sequence 3, 7, 11, 15, 19 arithmetic? If so, find the common difference.

💡 Show Solution

Step 1: Check if consecutive terms have the same difference: 7 - 3 = 4 11 - 7 = 4 15 - 11 = 4 19 - 15 = 4

Step 2: Determine if arithmetic: Since all differences are the same (4), this IS an arithmetic sequence.

Step 3: State the common difference: d = 4

Answer: Yes, it is arithmetic with common difference d = 4

4Problem 4medium

Question:

Find the 10th term of the sequence: 3,7,11,15,...3, 7, 11, 15, ...

💡 Show Solution

Step 1: Identify a1a_1 and dd a1=3,d=73=4a_1 = 3, \quad d = 7 - 3 = 4

Step 2: Use the explicit formula an=a1+(n1)da_n = a_1 + (n - 1)d

Step 3: Substitute n=10n = 10 a10=3+(101)(4)a_{10} = 3 + (10 - 1)(4) =3+9(4)= 3 + 9(4) =3+36= 3 + 36 =39= 39

Answer: a10=39a_{10} = 39

5Problem 5medium

Question:

Find the 10th term of the arithmetic sequence: 2, 5, 8, 11, ...

💡 Show Solution

Step 1: Identify the first term and common difference: a₁ = 2 (first term) d = 5 - 2 = 3 (common difference)

Step 2: Use the explicit formula: aₙ = a₁ + (n - 1)d

Step 3: Substitute to find the 10th term (n = 10): a₁₀ = 2 + (10 - 1)(3) a₁₀ = 2 + (9)(3) a₁₀ = 2 + 27 a₁₀ = 29

Step 4: Check by listing terms: 1st: 2, 2nd: 5, 3rd: 8, 4th: 11, 5th: 14, 6th: 17, 7th: 20, 8th: 23, 9th: 26, 10th: 29 ✓

Answer: a₁₀ = 29

6Problem 6medium

Question:

The 5th term of an arithmetic sequence is 17 and the 8th term is 26. Find the first term and common difference.

💡 Show Solution

Step 1: Write equations using aₙ = a₁ + (n - 1)d: For n = 5: a₅ = a₁ + 4d = 17 For n = 8: a₈ = a₁ + 7d = 26

Step 2: Set up a system of equations: a₁ + 4d = 17 ... (1) a₁ + 7d = 26 ... (2)

Step 3: Subtract equation (1) from equation (2): (a₁ + 7d) - (a₁ + 4d) = 26 - 17 3d = 9 d = 3

Step 4: Substitute d = 3 into equation (1): a₁ + 4(3) = 17 a₁ + 12 = 17 a₁ = 5

Step 5: Check: 5th term: 5 + 4(3) = 5 + 12 = 17 ✓ 8th term: 5 + 7(3) = 5 + 21 = 26 ✓

Answer: First term a₁ = 5, common difference d = 3

7Problem 7hard

Question:

The 5th term of an arithmetic sequence is 23 and the common difference is 4. Find the first term.

💡 Show Solution

Use the formula: an=a1+(n1)da_n = a_1 + (n - 1)d

Given: a5=23a_5 = 23, d=4d = 4, n=5n = 5

Substitute: 23=a1+(51)(4)23 = a_1 + (5 - 1)(4) 23=a1+1623 = a_1 + 16

Solve for a1a_1: a1=2316=7a_1 = 23 - 16 = 7

Check: If a1=7a_1 = 7 and d=4d = 4: 7,11,15,19,237, 11, 15, 19, 23

Answer: a1=7a_1 = 7

8Problem 8hard

Question:

Find the sum of the first 20 terms of the sequence: 3, 7, 11, 15, ...

💡 Show Solution

Step 1: Identify values: a₁ = 3 (first term) d = 7 - 3 = 4 (common difference) n = 20 (number of terms)

Step 2: Find the 20th term using aₙ = a₁ + (n - 1)d: a₂₀ = 3 + (20 - 1)(4) a₂₀ = 3 + 76 a₂₀ = 79

Step 3: Use the sum formula: Sₙ = n(a₁ + aₙ)/2 (This is the average of first and last term, times the number of terms)

Step 4: Substitute: S₂₀ = 20(3 + 79)/2 S₂₀ = 20(82)/2 S₂₀ = 1640/2 S₂₀ = 820

Alternative formula: Sₙ = n[2a₁ + (n-1)d]/2 S₂₀ = 20[2(3) + 19(4)]/2 = 20[6 + 76]/2 = 20(82)/2 = 820 ✓

Answer: Sum = 820