Arithmetic Sequences
Patterns and formulas for arithmetic sequences
Arithmetic Sequences
What is a Sequence?
A sequence is an ordered list of numbers called terms.
Example: 2, 4, 6, 8, 10, ...
Notation:
- a₁ = first term
- a₂ = second term
- a₃ = third term
- aₙ = nth term
Types of sequences:
- Arithmetic (constant difference)
- Geometric (constant ratio)
- Other patterns
What is an Arithmetic Sequence?
An arithmetic sequence has a constant difference between consecutive terms.
Examples:
- 3, 7, 11, 15, 19, ... (add 4 each time)
- 20, 15, 10, 5, 0, ... (subtract 5 each time)
- 1, 1.5, 2, 2.5, 3, ... (add 0.5 each time)
The constant difference is called the common difference (d).
Finding the Common Difference
The common difference (d) is found by subtracting consecutive terms.
Formula: d = a₂ - a₁ = a₃ - a₂ = aₙ₊₁ - aₙ
Example 1: 5, 9, 13, 17, 21
d = 9 - 5 = 4 Check: 13 - 9 = 4 ✓ Common difference: d = 4
Example 2: 30, 25, 20, 15, 10
d = 25 - 30 = -5 Common difference: d = -5 (decreasing sequence)
Example 3: 2, 5, 8, 11, 14
d = 5 - 2 = 3 Common difference: d = 3
Example 4: 7, 7, 7, 7, 7
d = 7 - 7 = 0 Common difference: d = 0 (constant sequence)
Writing the Next Terms
Add the common difference to find the next term.
Example 1: Find next 3 terms of 4, 7, 10, 13, ...
d = 3 Next terms: 13 + 3 = 16 16 + 3 = 19 19 + 3 = 22
Sequence: 4, 7, 10, 13, 16, 19, 22, ...
Example 2: Find next 3 terms of 100, 95, 90, 85, ...
d = -5 Next terms: 85 - 5 = 80 80 - 5 = 75 75 - 5 = 70
Sequence: 100, 95, 90, 85, 80, 75, 70, ...
The Explicit Formula
The explicit formula (or nth term formula) lets you find any term directly.
Formula: aₙ = a₁ + (n - 1)d
where:
- aₙ = nth term
- a₁ = first term
- n = position number
- d = common difference
Example 1: Find the 20th term of 3, 7, 11, 15, ...
a₁ = 3, d = 4, n = 20
a₂₀ = 3 + (20 - 1)(4) a₂₀ = 3 + 19(4) a₂₀ = 3 + 76 a₂₀ = 79
Example 2: Find the 50th term of 100, 95, 90, ...
a₁ = 100, d = -5, n = 50
a₅₀ = 100 + (50 - 1)(-5) a₅₀ = 100 + 49(-5) a₅₀ = 100 - 245 a₅₀ = -145
Example 3: Find the 15th term of 2, 9, 16, 23, ...
a₁ = 2, d = 7
a₁₅ = 2 + (15 - 1)(7) a₁₅ = 2 + 98 a₁₅ = 100
Writing the Explicit Formula
Given the sequence, write the formula for aₙ.
Example 1: 5, 8, 11, 14, 17, ...
a₁ = 5, d = 3
Formula: aₙ = 5 + (n - 1)(3) Simplified: aₙ = 5 + 3n - 3 = 3n + 2
Example 2: 20, 17, 14, 11, 8, ...
a₁ = 20, d = -3
Formula: aₙ = 20 + (n - 1)(-3) Simplified: aₙ = 20 - 3n + 3 = -3n + 23
Example 3: 4, 9, 14, 19, 24, ...
a₁ = 4, d = 5
Formula: aₙ = 4 + (n - 1)(5) = 5n - 1
Finding Which Term Has a Given Value
Set aₙ equal to the value and solve for n.
Example 1: In the sequence 3, 7, 11, 15, ..., which term equals 99?
Formula: aₙ = 3 + (n - 1)(4) = 4n - 1
Set equal: 4n - 1 = 99 4n = 100 n = 25
The 25th term equals 99.
Example 2: In sequence 50, 46, 42, 38, ..., which term equals 2?
Formula: aₙ = 50 + (n - 1)(-4) = -4n + 54
-4n + 54 = 2 -4n = -52 n = 13
The 13th term equals 2.
Example 3: In sequence 1, 6, 11, 16, ..., which term equals 101?
aₙ = 1 + (n - 1)(5) = 5n - 4
5n - 4 = 101 5n = 105 n = 21
The 21st term is 101.
Recursive Formula
A recursive formula defines each term using the previous term.
General form: aₙ = aₙ₋₁ + d with a₁ given
Example 1: 5, 9, 13, 17, ...
a₁ = 5 aₙ = aₙ₋₁ + 4
Example 2: 30, 25, 20, 15, ...
a₁ = 30 aₙ = aₙ₋₁ - 5
Recursive vs. Explicit:
- Recursive: need previous term
- Explicit: can find any term directly
Graphing Arithmetic Sequences
Plot points (n, aₙ) where n is term number.
Example: 2, 5, 8, 11, 14, ...
Points: (1, 2), (2, 5), (3, 8), (4, 11), (5, 14)
Observation: Points lie on a straight line! Slope of line = common difference d
The graph is discrete (individual points), not continuous.
Arithmetic Means
An arithmetic mean between two numbers is the average.
Example: Find arithmetic mean between 10 and 20.
Mean = (10 + 20)/2 = 15
Multiple means: Insert numbers to form arithmetic sequence.
Example: Insert 3 arithmetic means between 5 and 25.
We need: 5, ?, ?, ?, 25 (5 terms total)
a₁ = 5, a₅ = 25, n = 5
Use formula: 25 = 5 + (5 - 1)d 25 = 5 + 4d 20 = 4d d = 5
Sequence: 5, 10, 15, 20, 25
Sum of Arithmetic Sequence
The sum of n terms (Sₙ) has a special formula.
Formula 1: Sₙ = n(a₁ + aₙ)/2
Formula 2: Sₙ = n[2a₁ + (n - 1)d]/2
Example 1: Find sum of first 10 terms of 3, 7, 11, 15, ...
First find a₁₀: a₁₀ = 3 + (10 - 1)(4) = 39
Use Formula 1: S₁₀ = 10(3 + 39)/2 S₁₀ = 10(42)/2 S₁₀ = 210
Example 2: Find sum: 2 + 5 + 8 + ... (20 terms)
a₁ = 2, d = 3, n = 20
Use Formula 2: S₂₀ = 20[2(2) + (20 - 1)(3)]/2 S₂₀ = 20[4 + 57]/2 S₂₀ = 20(61)/2 S₂₀ = 610
Example 3: Sum of 1 + 2 + 3 + ... + 100
a₁ = 1, aₙ = 100, n = 100
S₁₀₀ = 100(1 + 100)/2 S₁₀₀ = 100(101)/2 S₁₀₀ = 5,050
Why the Sum Formula Works
Visual explanation: Sum = 1 + 2 + 3 + 4 + 5 Reverse = 5 + 4 + 3 + 2 + 1 Add: 6 + 6 + 6 + 6 + 6 = 5 × 6 = 30 So sum = 30/2 = 15
General: Sₙ = n(first + last)/2
Applications: Saving Money
Example: Save 15 second week, $20 third week, etc. How much saved after 20 weeks?
a₁ = 10, d = 5, n = 20
First find a₂₀: a₂₀ = 10 + (20 - 1)(5) = 105
Sum: S₂₀ = 20(10 + 105)/2 S₂₀ = 20(115)/2 S₂₀ = $1,150
Applications: Seating
Example: Theater has 20 rows. First row has 15 seats, each row has 2 more seats than previous. How many total seats?
a₁ = 15, d = 2, n = 20
a₂₀ = 15 + 19(2) = 53 seats in last row
Total: S₂₀ = 20(15 + 53)/2 = 20(68)/2 = 680 seats
Applications: Falling Objects
Example: Object falls 16 ft in 1st second, 48 ft in 2nd second, 80 ft in 3rd second, etc. How far in 10 seconds?
Sequence: 16, 48, 80, ... d = 32
a₁₀ = 16 + 9(32) = 304 ft in 10th second
Total distance: S₁₀ = 10(16 + 304)/2 = 1,600 ft
Identifying Arithmetic Sequences
Check if sequence is arithmetic: Calculate differences between consecutive terms. If all equal, it's arithmetic!
Example 1: 3, 6, 12, 24, ... 6 - 3 = 3 12 - 6 = 6 (different!) NOT arithmetic (this is geometric)
Example 2: 5, 8, 11, 14, ... 8 - 5 = 3 11 - 8 = 3 14 - 11 = 3 ✓ Arithmetic with d = 3
Common Mistakes to Avoid
-
Confusing term number with term value a₅ = 20 means 5th term is 20, not "a times 5"
-
Wrong formula Use aₙ = a₁ + (n - 1)d, not aₙ = a₁ + nd
-
Arithmetic errors with negatives If d = -3, then add -3 (subtract 3)
-
Forgetting to find d first Always identify common difference!
-
Not checking if sequence is arithmetic Calculate differences to verify
-
Mixing up sum formulas Sₙ needs (a₁ + aₙ)/2, not (a₁ + d)
Arithmetic vs. Geometric
Arithmetic: constant difference (add/subtract)
- 2, 5, 8, 11, ... (add 3)
Geometric: constant ratio (multiply/divide)
- 2, 6, 18, 54, ... (multiply by 3)
Other patterns:
- 1, 4, 9, 16, ... (perfect squares)
- 1, 1, 2, 3, 5, 8, ... (Fibonacci)
Real-World Examples
Arithmetic sequences appear in:
- Stacking objects (height increases by constant)
- Straight-line depreciation (value decreases by constant)
- Regular savings plans
- Seating arrangements
- Odometer readings at constant speed
- Rental fees (base + per day)
Quick Reference
Common difference: d = a₂ - a₁
Explicit formula: aₙ = a₁ + (n - 1)d
Recursive formula: aₙ = aₙ₋₁ + d
Sum formula: Sₙ = n(a₁ + aₙ)/2
Practice Strategy
Level 1: Find common difference
- Given sequence, find d
Level 2: Find next terms
- Continue the pattern
Level 3: Find specific term
- Use explicit formula
Level 4: Write formula
- Given sequence, find aₙ
Level 5: Applications
- Word problems with sequences
Tips for Success
- Always find d first
- Memorize: aₙ = a₁ + (n - 1)d
- Check work by calculating a few terms
- Verify sequence is arithmetic before using formulas
- Draw diagrams for word problems
- Remember n is position number, not the term value
- Practice identifying patterns
- Use sum formula for long sequences
- Graph sequences to visualize
- Connect to linear functions (same slope as d)
📚 Practice Problems
1Problem 1easy
❓ Question:
Find the next three terms: 5, 8, 11, 14, ...
💡 Show Solution
Step 1: Find the common difference (d): d = 8 - 5 = 3 Check: 11 - 8 = 3, 14 - 11 = 3 ✓
Step 2: Add the common difference to find the next terms: 5th term: 14 + 3 = 17 6th term: 17 + 3 = 20 7th term: 20 + 3 = 23
Step 3: Verify the pattern: 5, 8, 11, 14, 17, 20, 23 (each term increases by 3)
Answer: 17, 20, 23
2Problem 2easy
❓ Question:
Find the common difference:
💡 Show Solution
Subtract consecutive terms:
Check: ✓
Answer: Common difference =
3Problem 3easy
❓ Question:
Is the sequence 3, 7, 11, 15, 19 arithmetic? If so, find the common difference.
💡 Show Solution
Step 1: Check if consecutive terms have the same difference: 7 - 3 = 4 11 - 7 = 4 15 - 11 = 4 19 - 15 = 4
Step 2: Determine if arithmetic: Since all differences are the same (4), this IS an arithmetic sequence.
Step 3: State the common difference: d = 4
Answer: Yes, it is arithmetic with common difference d = 4
4Problem 4medium
❓ Question:
Find the 10th term of the sequence:
💡 Show Solution
Step 1: Identify and
Step 2: Use the explicit formula
Step 3: Substitute
Answer:
5Problem 5medium
❓ Question:
Find the 10th term of the arithmetic sequence: 2, 5, 8, 11, ...
💡 Show Solution
Step 1: Identify the first term and common difference: a₁ = 2 (first term) d = 5 - 2 = 3 (common difference)
Step 2: Use the explicit formula: aₙ = a₁ + (n - 1)d
Step 3: Substitute to find the 10th term (n = 10): a₁₀ = 2 + (10 - 1)(3) a₁₀ = 2 + (9)(3) a₁₀ = 2 + 27 a₁₀ = 29
Step 4: Check by listing terms: 1st: 2, 2nd: 5, 3rd: 8, 4th: 11, 5th: 14, 6th: 17, 7th: 20, 8th: 23, 9th: 26, 10th: 29 ✓
Answer: a₁₀ = 29
6Problem 6medium
❓ Question:
The 5th term of an arithmetic sequence is 17 and the 8th term is 26. Find the first term and common difference.
💡 Show Solution
Step 1: Write equations using aₙ = a₁ + (n - 1)d: For n = 5: a₅ = a₁ + 4d = 17 For n = 8: a₈ = a₁ + 7d = 26
Step 2: Set up a system of equations: a₁ + 4d = 17 ... (1) a₁ + 7d = 26 ... (2)
Step 3: Subtract equation (1) from equation (2): (a₁ + 7d) - (a₁ + 4d) = 26 - 17 3d = 9 d = 3
Step 4: Substitute d = 3 into equation (1): a₁ + 4(3) = 17 a₁ + 12 = 17 a₁ = 5
Step 5: Check: 5th term: 5 + 4(3) = 5 + 12 = 17 ✓ 8th term: 5 + 7(3) = 5 + 21 = 26 ✓
Answer: First term a₁ = 5, common difference d = 3
7Problem 7hard
❓ Question:
The 5th term of an arithmetic sequence is 23 and the common difference is 4. Find the first term.
💡 Show Solution
Use the formula:
Given: , ,
Substitute:
Solve for :
Check: If and : ✓
Answer:
8Problem 8hard
❓ Question:
Find the sum of the first 20 terms of the sequence: 3, 7, 11, 15, ...
💡 Show Solution
Step 1: Identify values: a₁ = 3 (first term) d = 7 - 3 = 4 (common difference) n = 20 (number of terms)
Step 2: Find the 20th term using aₙ = a₁ + (n - 1)d: a₂₀ = 3 + (20 - 1)(4) a₂₀ = 3 + 76 a₂₀ = 79
Step 3: Use the sum formula: Sₙ = n(a₁ + aₙ)/2 (This is the average of first and last term, times the number of terms)
Step 4: Substitute: S₂₀ = 20(3 + 79)/2 S₂₀ = 20(82)/2 S₂₀ = 1640/2 S₂₀ = 820
Alternative formula: Sₙ = n[2a₁ + (n-1)d]/2 S₂₀ = 20[2(3) + 19(4)]/2 = 20[6 + 76]/2 = 20(82)/2 = 820 ✓
Answer: Sum = 820
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