Inequality Word Problems
Real-world problems using inequalities
Inequality Word Problems
Introduction to Inequality Word Problems
While equations have exact answers, inequalities represent ranges of solutions. Many real-world situations involve minimum or maximum values, making inequalities the natural choice.
Key Difference:
- Equation: "The cost IS 50)
- Inequality: "The cost is AT MOST 50)
Understanding Inequality Language
Learning to translate words into inequality symbols is crucial:
Less Than (<):
- less than
- fewer than
- below
- under
Greater Than (>):
- greater than
- more than
- above
- over
- exceeds
Less Than or Equal To (≤):
- at most
- no more than
- maximum
- up to
- not more than
Greater Than or Equal To (≥):
- at least
- no less than
- minimum
- not less than
- no fewer than
The Problem-Solving Process
Step 1: Read Carefully Identify key words that indicate an inequality
Step 2: Define the Variable Let x = the unknown quantity
Step 3: Write the Inequality Translate the words into mathematical symbols
Step 4: Solve the Inequality Use algebraic techniques (remember to flip sign when multiplying/dividing by negative!)
Step 5: Interpret the Solution Answer in context, considering if fractional answers make sense
Step 6: Check Test a value from your solution to verify
Budget and Money Problems
These are the most common inequality word problems.
Example 1: Shopping Budget Problem: You have 12 each. How many shirts can you buy?
Let x = number of shirts Cost ≤ Budget
Inequality: 12x ≤ 75 12x ≤ 75 x ≤ 6.25
Interpretation: You can buy at most 6 shirts (can't buy 0.25 of a shirt!)
Check: 12(6) = 84 ✗ (over budget)
Example 2: Combined Purchases Problem: You want to buy notebooks at 2 each. You need at least 5 notebooks and have $25 total. How many pens can you buy?
Let x = number of pens Cost of notebooks: 5 × 15 Remaining for pens: 15 = $10
Inequality: 2x ≤ 10 x ≤ 5
Answer: You can buy at most 5 pens.
Example 3: Saving Money Problem: Maria has 15 per week. After how many weeks will she have at least $300?
Let x = number of weeks Starting amount + weekly savings ≥ goal
Inequality: 120 + 15x ≥ 300 15x ≥ 180 x ≥ 12
Answer: After at least 12 weeks.
Age Problems
Example 1: Minimum Age Problem: You must be at least 16 years old to get a driver's license. Sarah is 14. In how many years can she get her license?
Let x = years from now Current age + years ≥ minimum age
Inequality: 14 + x ≥ 16 x ≥ 2
Answer: In at least 2 years.
Example 2: Age Comparison Problem: Tom is 5 years older than his sister. Their combined ages are less than 30. If his sister is x years old, what are the possible ages?
Sister's age: x Tom's age: x + 5 Combined: x + (x + 5) < 30
Inequality: 2x + 5 < 30 2x < 25 x < 12.5
Answer: Sister is less than 12.5 years old (so at most 12 years old).
Geometry Problems
Example 1: Perimeter Constraint Problem: A rectangle has length 8 cm. If the perimeter must be at most 40 cm, what is the maximum width?
Let w = width Perimeter formula: P = 2l + 2w
Inequality: 2(8) + 2w ≤ 40 16 + 2w ≤ 40 2w ≤ 24 w ≤ 12
Answer: Maximum width is 12 cm.
Example 2: Triangle Inequality Problem: A triangle has sides of length 5 cm and 8 cm. What are the possible lengths of the third side?
The Triangle Inequality Theorem states that the sum of any two sides must be greater than the third side.
Let x = third side
Three inequalities:
- 5 + 8 > x → x < 13
- 5 + x > 8 → x > 3
- 8 + x > 5 → x > -3 (always true for positive x)
Combined: 3 < x < 13
Answer: The third side must be between 3 cm and 13 cm.
Example 3: Area Minimum Problem: A rectangle has length 15 inches. What width will give it an area of at least 90 square inches?
Let w = width Area formula: A = lw
Inequality: 15w ≥ 90 w ≥ 6
Answer: Width must be at least 6 inches.
Test Scores and Grades
Example 1: Average Grade Problem: Your test scores are 85, 92, 78, and 88. What must you score on the fifth test to have an average of at least 85?
Let x = fifth test score Average = sum ÷ number of tests
Inequality: (85 + 92 + 78 + 88 + x)/5 ≥ 85 (343 + x)/5 ≥ 85 343 + x ≥ 425 x ≥ 82
Answer: You need at least 82 on the fifth test.
Example 2: Grade Range Problem: To get a B, your average must be at least 80 but less than 90. You have three test scores: 75, 85, and 78. What range of scores on the fourth test will give you a B?
Let x = fourth test score
Lower bound (at least 80): (75 + 85 + 78 + x)/4 ≥ 80 238 + x ≥ 320 x ≥ 82
Upper bound (less than 90): (75 + 85 + 78 + x)/4 < 90 238 + x < 360 x < 122
Combined: 82 ≤ x < 122
Since maximum test score is typically 100: 82 ≤ x ≤ 100
Answer: You need between 82 and 100 on the fourth test.
Number Problems
Example 1: Consecutive Integers Problem: Find all sets of three consecutive integers whose sum is less than 50.
Let x = first integer Then x + 1 = second integer And x + 2 = third integer
Inequality: x + (x + 1) + (x + 2) < 50 3x + 3 < 50 3x < 47 x < 15.67
Answer: The first integer must be at most 15. Examples: (15, 16, 17), (14, 15, 16), etc.
Example 2: Number Relationships Problem: Five more than twice a number is at most 25. Find the possible values.
Let x = the number Twice the number: 2x Five more than twice: 2x + 5
Inequality: 2x + 5 ≤ 25 2x ≤ 20 x ≤ 10
Answer: The number is at most 10.
Distance and Travel Problems
Example 1: Speed Limit Problem: The speed limit is 65 mph. You travel for 3 hours. What is the maximum distance you can legally travel?
Let d = distance Using d = rt: d = 65 × 3
But this is a constraint: speed ≤ 65 So: d ≤ 65(3) d ≤ 195
Answer: Maximum distance is 195 miles.
Example 2: Travel Time Problem: You need to drive 240 miles and arrive in at most 4 hours. What is the minimum average speed?
Let r = average speed (rate) Using d = rt: 240 = r × 4
But time must be ≤ 4 hours: 240/r ≤ 4
Multiply both sides by r (assuming r > 0): 240 ≤ 4r 60 ≤ r
Answer: Minimum average speed is 60 mph.
Business and Profit Problems
Example 1: Break Even Problem: A company's costs are 8 per item produced. They sell items for $15 each. How many items must they sell to make a profit?
Let x = number of items
Revenue: 15x Cost: 500 + 8x Profit when Revenue > Cost
Inequality: 15x > 500 + 8x 7x > 500 x > 71.43
Answer: They must sell at least 72 items to make a profit.
Example 2: Sales Goal Problem: A salesperson earns 3500?
Let x = sales amount Total earnings: 2000 + 0.05x
Inequality: 2000 + 0.05x ≥ 3500 0.05x ≥ 1500 x ≥ 30,000
Answer: They must sell at least $30,000.
Mixture and Concentration Problems
Example 1: Solution Concentration Problem: You need a solution that is at least 20% acid. You have 10 liters of 15% acid solution. How much pure acid must you add?
Let x = liters of pure acid (100% acid)
Amount of acid after mixing ≥ 20% of total volume 0.15(10) + 1.00(x) ≥ 0.20(10 + x) 1.5 + x ≥ 2 + 0.20x 0.80x ≥ 0.5 x ≥ 0.625
Answer: Add at least 0.625 liters of pure acid.
Temperature Problems
Example 1: Temperature Range Problem: Water remains liquid between 32°F and 212°F. Write an inequality for liquid water temperature.
Let T = temperature
Compound inequality: 32 < T < 212
This can also be written as two separate inequalities: T > 32 AND T < 212
Example 2: Temperature Conversion Problem: In Celsius, what temperature range keeps water liquid?
Using F = (9/5)C + 32:
Lower bound: (9/5)C + 32 > 32 (9/5)C > 0 C > 0
Upper bound: (9/5)C + 32 < 212 (9/5)C < 180 C < 100
Answer: 0 < C < 100 (0°C to 100°C)
Common Mistakes to Avoid
-
Using = instead of ≤ or ≥ "At most" means ≤, not =
-
Wrong inequality symbol "At least 50" is x ≥ 50, not x > 50
-
Forgetting to flip the inequality When dividing by -2, must flip the sign!
-
Not considering realistic answers Can't buy 3.7 tickets - must round appropriately
-
Misinterpreting "less than" "5 less than x" is x - 5, not 5 - x
-
Forgetting units Is it dollars, hours, miles?
Interpreting Solutions
Discrete vs. Continuous:
Discrete (countable items like people, tickets): If x ≤ 6.8, then x ≤ 6 (round down) If x ≥ 3.2, then x ≥ 4 (round up)
Continuous (measurable quantities like time, distance): If x ≤ 6.8, answer is "at most 6.8" If x ≥ 3.2, answer is "at least 3.2"
Problem-Solving Strategy Checklist
Before solving:
- ☐ Identify key words (at least, at most, minimum, maximum)
- ☐ Determine if answer should be discrete or continuous
- ☐ Define variable clearly
While solving:
- ☐ Write inequality carefully
- ☐ Show all algebraic steps
- ☐ Remember to flip inequality when multiplying/dividing by negative
After solving:
- ☐ Interpret answer in context
- ☐ Round appropriately if needed
- ☐ Check with a test value
- ☐ Answer the actual question asked
Quick Reference - Key Phrases
| Phrase | Symbol | Example | |--------|--------|---------| | At least | ≥ | x ≥ 10 | | At most | ≤ | x ≤ 50 | | More than | > | x > 5 | | Less than | < | x < 20 | | No more than | ≤ | x ≤ 15 | | No less than | ≥ | x ≥ 8 | | Minimum | ≥ | x ≥ 12 | | Maximum | ≤ | x ≤ 100 | | Between | compound | 5 < x < 10 | | Exceeds | > | x > 75 |
Practice Tips
- Make a vocabulary list of inequality words
- Draw number lines to visualize solutions
- Always check if your answer makes sense in context
- Practice identifying whether to round up or down
- Remember: "at least" includes the number (≥)
- Remember: "more than" doesn't include the number (>)
- Write out what your variable represents
- Double-check inequality direction before and after solving
- Test your solution with boundary values
📚 Practice Problems
1Problem 1easy
❓ Question:
You have 8 each. Write and solve an inequality for the maximum number of books you can buy.
💡 Show Solution
Step 1: Define the variable: Let b = number of books
Step 2: Set up the inequality: Cost of books must be at most $50 8b ≤ 50
Step 3: Solve the inequality: b ≤ 50/8 b ≤ 6.25
Step 4: Interpret in context: You can't buy part of a book So b must be a whole number Maximum: b = 6 books
Step 5: Check: 6 books: 8(6) = 50 ✓ 7 books: 8(7) = 50 ✗
Answer: b ≤ 6.25; You can buy at most 6 books
2Problem 2easy
❓ Question:
Sarah wants to buy notebooks that cost $3 each. She has $20. What is the maximum number of notebooks she can buy?
💡 Show Solution
Let = number of notebooks
The cost must be at most $20:
Divide by 3:
Since she can't buy a fraction of a notebook:
Answer: Maximum of 6 notebooks
3Problem 3easy
❓ Question:
A taxi charges 2 per mile. You have $25. What is the maximum distance you can travel?
💡 Show Solution
Step 1: Define the variable: Let m = number of miles
Step 2: Identify costs: Pickup fee: 2 Total budget: $25
Step 3: Set up the inequality: 3 + 2m ≤ 25
Step 4: Solve: 2m ≤ 22 (subtract 3) m ≤ 11 (divide by 2)
Step 5: Check: 11 miles: 2(11) = 22 = 3 + 3 + 27 > $25 ✗
Answer: You can travel at most 11 miles
4Problem 4medium
❓ Question:
A taxi charges $5 plus $2 per mile. You have $25. What is the maximum distance you can travel?
💡 Show Solution
Let = miles traveled
Total cost:
This must be at most $25:
Subtract 5:
Divide by 2:
Answer: Maximum distance is 10 miles
5Problem 5medium
❓ Question:
Your test scores are 82, 78, and 85. What score do you need on the fourth test to have an average of at least 80?
💡 Show Solution
Step 1: Define the variable: Let x = score on the fourth test
Step 2: Write the average formula: Average = Sum of all scores / Number of tests Average = (82 + 78 + 85 + x)/4
Step 3: Set up the inequality: We want average ≥ 80 (82 + 78 + 85 + x)/4 ≥ 80
Step 4: Simplify the left side: (245 + x)/4 ≥ 80
Step 5: Solve: 245 + x ≥ 320 (multiply both sides by 4) x ≥ 75 (subtract 245)
Step 6: Check: If x = 75: (82 + 78 + 85 + 75)/4 = 320/4 = 80 ✓ If x = 74: (82 + 78 + 85 + 74)/4 = 319/4 = 79.75 < 80 ✗
Answer: You need at least 75 on the fourth test
6Problem 6medium
❓ Question:
A movie theater charges 7 for children. A group has $100 to spend. If they buy 5 adult tickets, how many children tickets can they buy?
💡 Show Solution
Step 1: Define the variable: Let c = number of children tickets
Step 2: Calculate cost of adult tickets: 5 adult tickets × 60
Step 3: Find remaining money: 60 = $40 available for children tickets
Step 4: Set up the inequality: Cost of children tickets ≤ Remaining money 7c ≤ 40
Step 5: Solve: c ≤ 40/7 c ≤ 5.71...
Step 6: Interpret: Can't buy partial tickets Maximum: c = 5 children tickets
Step 7: Verify the total: 5 adult tickets: 5 × 60 5 children tickets: 5 × 35 Total: 35 = 100 ✓
6 children would be: 42 = 100 ✗
Answer: They can buy at most 5 children tickets
7Problem 7hard
❓ Question:
Maria scored 85, 92, and 88 on her first three tests. What must she score on the fourth test to have an average of at least 90?
💡 Show Solution
Let = score on fourth test
Average formula:
Multiply both sides by 4:
Subtract 265:
Answer: She must score at least 95 on the fourth test
8Problem 8hard
❓ Question:
A phone plan costs 0.05 per text. A competitor charges $50/month with unlimited texts. For what number of texts is the first plan cheaper?
💡 Show Solution
Step 1: Define the variable: Let t = number of texts per month
Step 2: Write cost expressions: Plan 1: 0.05t Plan 2: $50 (flat rate)
Step 3: Set up the inequality: We want Plan 1 to cost less than Plan 2 40 + 0.05t < 50
Step 4: Solve: 0.05t < 10 (subtract 40) t < 10/0.05 (divide by 0.05) t < 200
Step 5: Alternative method (multiply by 100 first): 40 + 0.05t < 50 4000 + 5t < 5000 (multiply by 100) 5t < 1000 t < 200
Step 6: Interpret: Plan 1 is cheaper when you send fewer than 200 texts At exactly 200 texts, costs are equal Above 200 texts, Plan 2 (unlimited) is cheaper
Step 7: Verify: t = 199: 0.05(199) = 9.95 = 50 ✓ t = 200: 0.05(200) = 10 = 50 (equal) t = 201: 0.05(201) = 10.05 = 50 ✗
Answer: Plan 1 is cheaper when sending fewer than 200 texts per month (t < 200)
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